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Integrals — chapter notes

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1. Antiderivatives and standard integrals

If ddxF(x)=f(x)\dfrac{d}{dx}F(x) = f(x) on an interval, FF is an antiderivative of ff and ∫f(x) dx=F(x)+C\displaystyle\int f(x)\,dx = F(x) + C, where CC is the constant of integration. Two antiderivatives of the same function differ by a constant, so the graphs of F(x)+CF(x) + C form a family of vertically shifted curves.

Integration is linear: ∫[kf±g] dx=k∫f dx±∫g dx\displaystyle\int [kf \pm g]\,dx = k\int f\,dx \pm \int g\,dx. Every derivative rule gives an integration rule (see the table). A given point on the curve fixes CC.

Example: ∫(6x2−4x+5cos⁡x)dx=2x3−4log⁡∣x∣+5sin⁡x+C\displaystyle\int \left(6x^2 - \dfrac4x + 5\cos x\right)dx = 2x^3 - 4\log|x| + 5\sin x + C.

Read each derivative rule backwards.
Function f(x)f(x)∫f(x) dx\displaystyle\int f(x)\,dx
xnx^n (n≠−1)(n \ne -1)xn+1n+1+C\dfrac{x^{n+1}}{n+1} + C
1x\dfrac1xlog⁡∣x∣+C\log|x| + C
exe^xex+Ce^x + C
axa^xaxlog⁡a+C\dfrac{a^x}{\log a} + C
sin⁡x\sin x−cos⁡x+C-\cos x + C
cos⁡x\cos xsin⁡x+C\sin x + C
sec⁡2x\sec^2 xtan⁡x+C\tan x + C
sec⁡xtan⁡x\sec x\tan xsec⁡x+C\sec x + C

Formulas

  • Power rule
    ∫xn dx=xn+1n+1+C(n≠−1)\int x^n\,dx = \frac{x^{n+1}}{n+1} + C \quad (n \ne -1)
  • Reciprocal
    ∫dxx=log⁡∣x∣+C\int \frac{dx}{x} = \log|x| + C

Key terms

Antiderivative (primitive)

A function FF with F′=fF' = f.

Indefinite integral

The family ∫f(x) dx=F(x)+C\displaystyle\int f(x)\,dx = F(x) + C.

2. Integration by substitution

If the integrand contains a function g(x)g(x) together with its derivative g′(x)g'(x), put t=g(x)t = g(x), dt=g′(x) dxdt = g'(x)\,dx, integrate in tt and substitute back.

Trigonometric integrals often need an identity first: sin⁡2x=1−cos⁡2x2\sin^2 x = \dfrac{1 - \cos 2x}{2}, cos⁡2x=1+cos⁡2x2\cos^2 x = \dfrac{1 + \cos 2x}{2}, tan⁡2x=sec⁡2x−1\tan^2 x = \sec^2 x - 1; for odd powers such as sin⁡3x\sin^3 x keep one factor for dtdt.

Useful results: ∫tan⁡x dx=log⁡∣sec⁡x∣+C\displaystyle\int \tan x\,dx = \log|\sec x| + C, ∫cot⁡x dx=log⁡∣sin⁡x∣+C\displaystyle\int \cot x\,dx = \log|\sin x| + C, ∫sec⁡x dx=log⁡∣sec⁡x+tan⁡x∣+C\displaystyle\int \sec x\,dx = \log|\sec x + \tan x| + C, ∫cosec⁡x dx=log⁡∣cosec⁡x−cot⁡x∣+C\displaystyle\int \operatorname{cosec} x\,dx = \log|\operatorname{cosec} x - \cot x| + C.

Substitution is the chain rule run backwards.

Formulas

  • Derivative over function
    ∫f′(x)f(x) dx=log⁡∣f(x)∣+C\int \frac{f'(x)}{f(x)}\,dx = \log|f(x)| + C
  • Substitution
    ∫f(g(x)) g′(x) dx=∫f(t) dt\int f(g(x))\,g'(x)\,dx = \int f(t)\,dt

Key terms

Substitution

Changing the variable to t=g(x)t = g(x) so that the integral becomes a standard one.

3. Special forms with quadratics

For a>0a > 0 learn the six results in the table. For ∫dxax2+bx+c\displaystyle\int \dfrac{dx}{ax^2 + bx + c} or ∫dxax2+bx+c\displaystyle\int \dfrac{dx}{\sqrt{ax^2 + bx + c}}, complete the square and use the matching form.

For ∫px+qax2+bx+c dx\displaystyle\int \dfrac{px + q}{ax^2 + bx + c}\,dx, write px+q=Addx(ax2+bx+c)+Bpx + q = A\dfrac{d}{dx}(ax^2 + bx + c) + B: the AA part gives Alog⁡∣ax2+bx+c∣A\log|ax^2 + bx + c|, the BB part is a special form. With a square root in the denominator, the AA part gives 2Aax2+bx+c2A\sqrt{ax^2 + bx + c}.

Example: ∫dxx2−8x+25=13tan⁡−1x−43+C\displaystyle\int \dfrac{dx}{x^2 - 8x + 25} = \dfrac13\tan^{-1}\dfrac{x - 4}{3} + C.

Learn the six; every quadratic denominator is turned into one of them.
IntegrandIntegral
1x2−a2\dfrac{1}{x^2 - a^2}12alog⁡∣x−ax+a∣+C\dfrac{1}{2a}\log\left|\dfrac{x - a}{x + a}\right| + C
1a2−x2\dfrac{1}{a^2 - x^2}12alog⁡∣a+xa−x∣+C\dfrac{1}{2a}\log\left|\dfrac{a + x}{a - x}\right| + C
1x2+a2\dfrac{1}{x^2 + a^2}1atan⁡−1xa+C\dfrac1a\tan^{-1}\dfrac xa + C
1x2−a2\dfrac{1}{\sqrt{x^2 - a^2}}log⁡∣x+x2−a2∣+C\log\left|x + \sqrt{x^2 - a^2}\right| + C
1a2−x2\dfrac{1}{\sqrt{a^2 - x^2}}sin⁡−1xa+C\sin^{-1}\dfrac xa + C
1x2+a2\dfrac{1}{\sqrt{x^2 + a^2}}log⁡∣x+x2+a2∣+C\log\left|x + \sqrt{x^2 + a^2}\right| + C

Formulas

  • Inverse tangent form
    ∫dxx2+a2=1atan⁡−1xa+C\int \frac{dx}{x^2 + a^2} = \frac1a\tan^{-1}\frac xa + C
  • Inverse sine form
    ∫dxa2−x2=sin⁡−1xa+C\int \frac{dx}{\sqrt{a^2 - x^2}} = \sin^{-1}\frac xa + C

Key terms

Completing the square

Writing x2+bx+cx^2 + bx + c as (x+b2)2+c−b24\left(x + \dfrac b2\right)^2 + c - \dfrac{b^2}{4}.

4. Partial fractions

A rational function P(x)Q(x)\dfrac{P(x)}{Q(x)} is proper if deg⁡P<deg⁡Q\deg P < \deg Q; otherwise divide first. A proper function is split according to the factors of Q(x)Q(x) (table). Find the constants by putting convenient values of xx (zeros of the factors) and by comparing coefficients.

Each Ax−a\dfrac{A}{x - a} integrates to Alog⁡∣x−a∣A\log|x - a|; each B(x−a)2\dfrac{B}{(x - a)^2} to −Bx−a-\dfrac{B}{x - a}; Bx+Cx2+bx+c\dfrac{Bx + C}{x^2 + bx + c} splits into a log part and an inverse tangent part.

Example: x+5(x−1)(x+2)=2x−1−1x+2\dfrac{x + 5}{(x - 1)(x + 2)} = \dfrac{2}{x - 1} - \dfrac{1}{x + 2}.

Divide first if the fraction is improper (numerator degree ≥ denominator degree).
Denominator factorPartial fractions
(x−a)(x−b)(x - a)(x - b)Ax−a+Bx−b\dfrac{A}{x - a} + \dfrac{B}{x - b}
(x−a)2(x−b)(x - a)^2(x - b)Ax−a+B(x−a)2+Cx−b\dfrac{A}{x - a} + \dfrac{B}{(x - a)^2} + \dfrac{C}{x - b}
(x−a)(x2+bx+c)(x - a)(x^2 + bx + c)Ax−a+Bx+Cx2+bx+c\dfrac{A}{x - a} + \dfrac{Bx + C}{x^2 + bx + c}

Formulas

  • Distinct linear factors
    px+q(x−a)(x−b)=Ax−a+Bx−b\frac{px + q}{(x - a)(x - b)} = \frac{A}{x - a} + \frac{B}{x - b}

Key terms

Proper rational function

Degree of numerator less than degree of denominator.

Partial fractions

Simpler fractions whose sum is the given rational function.

5. Integration by parts

∫u dv=uv−∫v du\displaystyle\int u\,dv = uv - \int v\,du. Choose uu in the order inverse trigonometric, logarithmic, algebraic, trigonometric, exponential. Sometimes the formula is used twice, or the original integral reappears and is solved for (as in ∫eaxsin⁡bx dx\displaystyle\int e^{ax}\sin bx\,dx).

Special pattern: ∫ex[f(x)+f′(x)] dx=exf(x)+C\displaystyle\int e^x[f(x) + f'(x)]\,dx = e^xf(x) + C.

Results proved by parts (table): ∫a2−x2 dx\displaystyle\int \sqrt{a^2 - x^2}\,dx, ∫x2+a2 dx\displaystyle\int \sqrt{x^2 + a^2}\,dx, ∫x2−a2 dx\displaystyle\int \sqrt{x^2 - a^2}\,dx.

$\displaystyle\int u\,dv = uv - \int v\,du$: choose $u$ from the top of the list.
Priority for uuTypeExample
1Inverse trigtan⁡−1x\tan^{-1}x
2Logarithmiclog⁡x\log x
3Algebraicx2x^2
4Trigonometricsin⁡x\sin x
5Exponentialexe^x

Formulas

  • Integration by parts
    ∫u dv=uv−∫v du\int u\,dv = uv - \int v\,du
  • Exponential pattern
    ∫ex[f(x)+f′(x)] dx=exf(x)+C\int e^x[f(x) + f'(x)]\,dx = e^xf(x) + C

Key terms

By parts

The product rule reversed: ∫u dv=uv−∫v du\int u\,dv = uv - \int v\,du.

6. Definite integrals and the fundamental theorem

Fundamental theorem of calculus (stated without proof): if ff is continuous on [a,b][a, b] and F′=fF' = f, then ∫abf(x) dx=F(b)−F(a)=[F(x)]ab\displaystyle\int_a^b f(x)\,dx = F(b) - F(a) = \left[F(x)\right]_a^b. No constant is needed. For f≥0f \ge 0 the value is the area under the curve between x=ax = a and x=bx = b.

When substituting in a definite integral, change the limits too: ∫012xex2 dx=∫01et dt=e−1\displaystyle\int_0^1 2xe^{x^2}\,dx = \int_0^1 e^t\,dt = e - 1.

Not in the 2026–27 syllabus: the definite integral as the limit of a sum.

  • y=3x2+1y = 3x^2 + 1
$\displaystyle\int_0^2 (3x^2 + 1)\,dx = 10$: the area between the curve, the axis and the two dashed lines.

Formulas

  • Fundamental theorem
    ∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx = F(b) - F(a)

Key terms

Definite integral

The number ∫abf(x) dx=F(b)−F(a)\displaystyle\int_a^b f(x)\,dx = F(b) - F(a).

Limits of integration

The lower limit aa and the upper limit bb.

7. Properties of definite integrals

  • ∫abf=−∫baf\displaystyle\int_a^b f = -\int_b^a f and ∫aaf=0\displaystyle\int_a^a f = 0.
  • ∫abf=∫acf+∫cbf\displaystyle\int_a^b f = \int_a^c f + \int_c^b f: split where the formula changes, e.g. ∫04∣x−1∣ dx=12+92=5\displaystyle\int_0^4 |x - 1|\,dx = \dfrac12 + \dfrac92 = 5.
  • ∫abf(x) dx=∫abf(a+b−x) dx\displaystyle\int_a^b f(x)\,dx = \int_a^b f(a + b - x)\,dx, and ∫0af(x) dx=∫0af(a−x) dx\displaystyle\int_0^a f(x)\,dx = \int_0^a f(a - x)\,dx: write II both ways and add.
  • ∫−aaf=0\displaystyle\int_{-a}^{a} f = 0 if ff is odd; ∫−aaf=2∫0af\displaystyle\int_{-a}^{a} f = 2\int_0^a f if ff is even.
  • ∫02af=2∫0af\displaystyle\int_0^{2a} f = 2\int_0^a f if f(2a−x)=f(x)f(2a - x) = f(x), and 00 if f(2a−x)=−f(x)f(2a - x) = -f(x).
  • y=∣x−1∣y = |x - 1|
Split at the corner: $\dfrac12 + \dfrac92 = 5$.
  • odd: x3cos⁡xx^3\cos x
  • even: x2x^2
Odd: $\displaystyle\int_{-a}^{a} = 0$. Even: $\displaystyle\int_{-a}^{a} = 2\int_0^a$.

Formulas

  • Mirror property
    ∫0af(x) dx=∫0af(a−x) dx\int_0^a f(x)\,dx = \int_0^a f(a - x)\,dx

Key terms

Odd function

f(−x)=−f(x)f(-x) = -f(x), e.g. x3x^3, sin⁡x\sin x.

Even function

f(−x)=f(x)f(-x) = f(x), e.g. x2x^2, cos⁡x\cos x, ∣x∣|x|.

Exam tips

How marks are awarded

  • Indefinite integral (2–3 marks): method set up (substitution with dtdt, split numerator, partial-fraction form), each part integrated, final answer with +C+ C.
  • Partial fractions / by parts (3–5 marks): correct form, constants, each integral, final answer.
  • Definite integral (2–5 marks): antiderivative or property, limits applied (new limits after substitution), simplified value.

Common mistakes

  1. Forgetting +C+ C, or adding it to a definite integral.
  2. Writing log⁡x\log x for ∫dxx\displaystyle\int \dfrac{dx}{x} instead of log⁡∣x∣\log|x|.
  3. Losing the factor from dtdt (for example x2 dx=dt3x^2\,dx = \dfrac{dt}{3}).
  4. Using 1a\dfrac1a instead of 12a\dfrac{1}{2a} in the log forms (and vice versa for tan⁡−1\tan^{-1}).
  5. Writing partial fractions for an improper fraction without dividing first.
  6. Missing the second fraction for a repeated factor.
  7. Not changing the limits after substituting in a definite integral.
  8. Treating ∫−aa\displaystyle\int_{-a}^{a} of an even function as 00.