Skip to content
Skip to page content
soylai.com

Work, Energy and Simple Machines — Notes

6 sections 5 min readBeta

1. Work done by a force

Work is done when a force moves a body. For a force FF along the displacement ss, W=FsW = Fs; in general W=Fscos⁡θW = Fs\cos\theta, where θ\theta is the angle between the force and the displacement. The unit is the joule (J), 1 J=1 N m1\ \text{J} = 1\ \text{N m}. Work is a scalar.

  • θ=0∘\theta = 0^\circ: positive work (the force helps the motion).
  • θ=90∘\theta = 90^\circ: zero work (for example the lift on a trunk carried along a level road).
  • θ=180∘\theta = 180^\circ: negative work (friction or brakes).
  • No displacement means no work. On a force–displacement graph the area under the line is the work done.
Work can be positive, zero or negative.
Work = area under the force–displacement graph.

Formulas

  • Work done by a constant force
    W=Fscos⁡θW = Fs\cos\theta

Key terms

Work

Force times displacement in the direction of the force; unit joule.

Joule

The work done when a force of 1 N moves a body 1 m along the force.

Negative work

Work done by a force that acts opposite to the displacement.

2. Kinetic energy

Energy is the capacity to do work, measured in joules. Kinetic energy is the energy of a moving body. From v2=u2+2asv^2 = u^2 + 2as with u=0u = 0 and F=maF = ma, the work done in giving a body speed vv is W=Fs=ma⋅v2/2a=12mv2W = Fs = ma \cdot v^2/2a = \tfrac{1}{2}mv^2, so KE=12mv2\text{KE} = \tfrac{1}{2}mv^2 Doubling the speed makes the KE four times as large; doubling the mass doubles it.

  • mass 2 kg: KE = v²
Doubling the speed makes the kinetic energy four times as large.

Formulas

  • Kinetic energy
    KE=12mv2\text{KE} = \tfrac{1}{2}mv^2

Key terms

Energy

The capacity to do work; unit joule.

Kinetic energy

The energy a body has because of its motion, ½mv².

3. Potential energy and the work–energy theorem

Gravitational potential energy is the energy a body has because of its height. Lifting a body of mass mm at steady speed needs a force mgmg, so the work done in raising it by hh is W=mghW = mgh, stored as PE=mgh\text{PE} = mgh (with g=9.8 m s−2g = 9.8\ \text{m s}^{-2}, measured from a chosen reference level).

Work–energy theorem: the net work done on a body equals the change in its kinetic energy, Wnet=12mv2−12mu2W_\text{net} = \tfrac{1}{2}mv^2 - \tfrac{1}{2}mu^2. Brakes do negative work and reduce the KE to zero.

Table linking net work to the change in kinetic energy and the motion
Net work on a bodyChange in KEMotion
positiveincreasesspeeds up
negativedecreasesslows down
zerononesteady speed

Formulas

  • Gravitational potential energy
    PE=mgh\text{PE} = mgh
  • Work–energy theorem
    Wnet=ΔKEW_\text{net} = \Delta \text{KE}

Key terms

Potential energy

Stored energy due to position or condition; mgh near the Earth.

Work–energy theorem

Net work done on a body equals its change in kinetic energy.

4. Conservation of energy

Energy can neither be created nor destroyed; it changes from one form to another. Mechanical energy = KE + PE. For a freely falling body, a frictionless slide, a roller-coaster or an ideal pendulum, the mechanical energy stays constant: as PE falls, KE rises by the same amount. From rest at height HH, the speed at height hh is v=2g(H−h)v = \sqrt{2g(H - h)}, which does not depend on the mass.

Examples of transformations: a fan (electrical to kinetic), a solar cell (light to electrical), a dam (potential to kinetic to electrical), burning gas (chemical to heat and light). In real systems some energy becomes heat.

PE falls and KE rises by the same amount; the total stays constant.
Lower on the track means faster: PE changes into KE.

Formulas

  • Conservation of mechanical energy
    KE+PE=constant\text{KE} + \text{PE} = \text{constant}
  • Speed after a fall of height h from rest
    v=2ghv = \sqrt{2gh}

Key terms

Law of conservation of energy

Energy is neither created nor destroyed; the total stays constant.

Mechanical energy

The sum of kinetic and potential energy.

5. Power and commercial unit of energy

Power is the rate of doing work: P=W/tP = W/t. The SI unit is the watt (W), 1 W=1 J s−11\ \text{W} = 1\ \text{J s}^{-1}; 1 kW=1000 W1\ \text{kW} = 1000\ \text{W}. The commercial unit of electrical energy is the kilowatt hour (kWh), also called a unit: 1 kWh=3.6×1061\ \text{kWh} = 3.6 \times 10^6 J.

Energy in kWh = power in kW × time in hours. A 1.5 kW geyser used for 20 minutes uses 1.5×2060=0.501.5 \times \tfrac{20}{60} = 0.50 kWh.

Table of the watt, kilowatt and kilowatt hour with their values
UnitValue
1 watt (W)1 joule per second
1 kilowatt (kW)1000 W
1 kilowatt hour (kWh)3.6 × 10⁶ J
Energy in kWhpower in kW × time in hours

Formulas

  • Power
    P=WtP = \dfrac{W}{t}

Key terms

Power

Work done per unit time; unit watt.

Watt

One joule per second.

Kilowatt hour

Energy used by a 1 kW device in 1 hour, 3.6 × 10⁶ J.

6. Simple machines: levers, pulleys and efficiency

A simple machine changes the size or direction of a force. MA=load/effort\text{MA} = \text{load}/\text{effort} (no unit). A machine never gives more work than it receives.

  • Lever: MA=effort arm/load arm\text{MA} = \text{effort arm}/\text{load arm}. Class I: fulcrum in the middle (seesaw). Class II: load in the middle (wheelbarrow), MA > 1. Class III: effort in the middle (tongs), MA < 1.
  • Pulleys: single fixed MA = 1 (changes direction only); single movable MA = 2; for an ideal block and tackle MA = number of strands supporting the load.
  • Efficiency η=work outputwork input×100 %\eta = \dfrac{\text{work output}}{\text{work input}} \times 100\,\%, and η=MA/VR×100 %\eta = \text{MA}/\text{VR} \times 100\,\%, where VR is the distance moved by the effort divided by that moved by the load. Real machines have η<100 %\eta < 100\,\%.
Three classes of lever: the position of the fulcrum, load and effort decides the class.
Mechanical advantage of an ideal pulley = number of strands supporting the load.

Formulas

  • Mechanical advantage of a lever
    MA=loadeffort=effort armload arm\text{MA} = \dfrac{\text{load}}{\text{effort}} = \dfrac{\text{effort arm}}{\text{load arm}}
  • Efficiency
    η=outputinput×100 %\eta = \dfrac{\text{output}}{\text{input}} \times 100\,\%

Key terms

Mechanical advantage

Load divided by effort.

Fulcrum

The fixed point about which a lever turns.

Efficiency

Useful work output divided by work input, as a percentage.

Exam tips

  • Write the formula first, then substitute with units (J, W, N, m, kg, m s⁻¹); state g = 9.8 m s⁻².
  • Say whether work is positive, zero or negative and why (the angle).
  • Square the speed in KE; use the work–energy theorem for stopping problems.
  • Free fall and frictionless slopes: mgh = ½mv², and the mass cancels.
  • kWh = kW × hours; 1 kWh = 3.6 × 10⁶ J.
  • MA = load ÷ effort = effort arm ÷ load arm; count only supporting strands in a pulley; efficiency stays below 100 %.