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Linear Inequations — chapter notes

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1. Linear inequations and the four signs

A linear inequation in one variable compares two linear expressions with one of the signs <<, ≤\le, >>, ≥\ge, for example 3x+2<143x + 2 < 14.

  • << and >> are strict: the boundary number is not a solution.
  • ≤\le and ≥\ge include the boundary: x=3x = 3 satisfies x≤3x \le 3 but not x<3x < 3.
The sign decides whether the boundary number belongs.
SignRead asExampleIs x=3x = 3 a solution?
<<is less thanx<3x < 3no
≤\leis less than or equal tox≤3x \le 3yes
>>is greater thanx>3x > 3no
≥\geis greater than or equal tox≥3x \ge 3yes

Key terms

Linear inequation

A statement such as ax+b<cax + b < c (or with ≤\le, >>, ≥\ge) in which the variable has power 11.

Strict inequality

One with << or >>; the boundary value is excluded.

2. Replacement set and solution set

The replacement set (domain) is the set from which xx is taken: N={1,2,3,…}\mathbb{N} = \{1, 2, 3, \ldots\}, W={0,1,2,…}\mathbb{W} = \{0, 1, 2, \ldots\}, Z={…,−1,0,1,…}\mathbb{Z} = \{\ldots, -1, 0, 1, \ldots\} or R\mathbb{R}, or a set given in the question. The solution set is the subset whose members make the inequation true.

Example: 3x−2≤73x - 2 \le 7 gives x≤3x \le 3: over N\mathbb{N}, {1,2,3}\{1, 2, 3\}; over W\mathbb{W}, {0,1,2,3}\{0, 1, 2, 3\}; over Z\mathbb{Z}, {…,1,2,3}\{\ldots, 1, 2, 3\}.

The four replacement sets used in this chapter.
Replacement setSymbolMembers
Natural numbersN\mathbb{N}{1,2,3,…}\{1, 2, 3, \ldots\}
Whole numbersW\mathbb{W}{0,1,2,3,…}\{0, 1, 2, 3, \ldots\}
IntegersZ\mathbb{Z}{…,−2,−1,0,1,2,…}\{\ldots, -2, -1, 0, 1, 2, \ldots\}
Real numbersR\mathbb{R}all numbers on the number line, including fractions and decimals
One inequation, four different solution sets.
Replacement setSolution set of 3x−2≤73x - 2 \le 7
N\mathbb{N}{1,2,3}\{1, 2, 3\}
W\mathbb{W}{0,1,2,3}\{0, 1, 2, 3\}
Z\mathbb{Z}{…,1,2,3}\{\ldots, 1, 2, 3\}
R\mathbb{R}{x:x∈R, x≤3}\{x : x \in \mathbb{R},\ x \le 3\}

Key terms

Replacement set

The set of values the variable may take.

Solution set

The members of the replacement set that satisfy the inequation.

Empty set

A solution set with no members, written ϕ\phi or { }\{\ \}.

3. Rules for solving

An inequation keeps its solution set when you

  • add or subtract the same number (or expression) on both sides;
  • multiply or divide both sides by the same positive number.

Then solve as for an equation: remove brackets, clear fractions with the LCM (multiply every term), collect xx terms on one side and numbers on the other.

Example: x3−1≤x−24\dfrac{x}{3} - 1 \le \dfrac{x - 2}{4}; multiply by 1212: 4x−12≤3x−64x - 12 \le 3x - 6, so x≤6x \le 6.

Only a negative multiplier or divisor reverses the sign.
Do this to both sides of 2<72 < 7ResultSign
Add 557<127 < 12unchanged
Subtract 33−1<4-1 < 4unchanged
Multiply by 448<288 < 28unchanged
Divide by 221<3.51 < 3.5unchanged
Multiply by −3-3−6>−21-6 > -21reversed
Divide by −1-1−2>−7-2 > -7reversed
Testing members agrees with solving: $x < 4$.
xx3x+23x + 2Less than 1414?
0022yes
1155yes
2288yes
331111yes
441414no
551717no

Formulas

  • Adding the same number
    a<b⇒a+c<b+ca < b \Rightarrow a + c < b + c
  • Multiplying by a positive number
    a<b, k>0⇒ka<kba < b,\ k > 0 \Rightarrow ka < kb

Key terms

Equivalent inequations

Inequations with the same solution set.

4. Multiplying or dividing by a negative number

Multiplying or dividing both sides by a negative number reverses the sign: << becomes >> and ≤\le becomes ≥\ge.

Why: multiplying by −1-1 reflects the number line in 00, so the order of any two numbers is turned round: 2<52 < 5 but −2>−5-2 > -5.

Example: 7−3x≥−8⇒−3x≥−15⇒x≤57 - 3x \ge -8 \Rightarrow -3x \ge -15 \Rightarrow x \le 5 (dividing by −3-3).

Dots at $2$ and $5$ and at their negatives: $2 < 5$, but $-2 > -5$.
Dots at $1, 2, 3, 4$ and $5$.

Formulas

  • Multiplying by a negative number
    a<b, k<0⇒ka>kba < b,\ k < 0 \Rightarrow ka > kb

Key terms

Reversing the sign

Changing << to >> (or ≤\le to ≥\ge) when both sides are multiplied or divided by a negative number.

5. Combined (double) inequations

a<px+q≤ba < px + q \le b means a<px+qa < px + q and px+q≤bpx + q \le b.

  • When xx appears only in the middle, do the same step to all three parts; dividing by a negative number reverses both signs. Rewrite with the smaller number on the left.
  • When xx appears in all three parts (e.g. 3x−7<2x+1≤4x+63x - 7 < 2x + 1 \le 4x + 6), split it into two inequations and take the common part.

Example: 5<11−2x≤17⇒−6<−2x≤6⇒3>x≥−35 < 11 - 2x \le 17 \Rightarrow -6 < -2x \le 6 \Rightarrow 3 > x \ge -3, i.e. −3≤x<3-3 \le x < 3.

Solving a combined (double) inequation.
Every step acts on all three parts.
StepAll three partsResult
Start−3≤2x+1<9-3 \le 2x + 1 < 9
Subtract 11−3−1-3 - 1, 2x+1−12x + 1 - 1, 9−19 - 1−4≤2x<8-4 \le 2x < 8
Divide by 22positive, so signs stay−2≤x<4-2 \le x < 4

Key terms

Combined inequation

Two inequations written together, such as −3≤2x+1<9-3 \le 2x + 1 < 9.

6. Representing solution sets on the number line

  • x∈Nx \in \mathbb{N}, W\mathbb{W} or Z\mathbb{Z}: separate filled dots at the members; three dots (…\ldots) or an arrow shows that the set goes on.
  • x∈Rx \in \mathbb{R}: a thick line, with a filled circle at an included end point (≤\le, ≥\ge), an open circle at an excluded end point (<<, >>), and an arrow if the set goes on for ever.
  • Reading a graph: open circle →\to strict sign, filled circle →\to sign with "or equal to".
Top: a filled circle at $1$, so $1$ is included. Bottom: an open circle at $1$, so $1$ is excluded.
Integers: dots at $-1, 0, 1, 2$. Real numbers: an open circle at $-2$, a filled circle at $2$ and a thick line.
An open circle at $-3$ and a filled circle at $1$, joined by a thick line.

Key terms

Filled circle

Marks an end point that belongs to the solution set.

Open circle

Marks an end point that does not belong to the solution set.

7. Two inequations: intersection, union and the empty set

For A={x:…}A = \{x : \ldots\} and B={x:…}B = \{x : \ldots\}, solve each separately.

  • A∩BA \cap B: numbers in both, the overlap of the two graphs. Example: x>−2x > -2 and x≤4x \le 4 give −2<x≤4-2 < x \le 4.
  • A∪BA \cup B: numbers in at least one of them.
  • If the graphs do not overlap (x>4x > 4 and x<2x < 2), A∩B=ϕA \cap B = \phi.
Row A: an open circle at $-2$. Row B: a filled circle at $4$. The overlap runs from the open circle at $-2$ to the filled circle at $4$.
Top: an open circle at $4$, arrow to the right. Bottom: an open circle at $2$, arrow to the left. The graphs never overlap.

Key terms

Intersection

The set of numbers satisfying both inequations, A∩BA \cap B.

Union

The set of numbers satisfying at least one inequation, A∪BA \cup B.

Exam tips

How marks are awarded

  • Solve and write the solution set (2–3 marks): correct steps 1–2; solution set in the right form 1.
  • Combined inequation (3–4 marks): same step on all parts 1; reversal of both signs 1; solution set 1; number line 1.
  • Number line (1 mark): dots for N\mathbb{N}, W\mathbb{W}, Z\mathbb{Z}; thick line for R\mathbb{R}; filled or open circles; arrows.
  • 10-mark structured question: parts (a), (b), (c) usually 3 + 3 + 4; show all working.

Common mistakes

  1. Not reversing the sign when multiplying or dividing by a negative number (or reversing only one sign of a combined inequation).
  2. Including 00 in N\mathbb{N}, or negative numbers in W\mathbb{W}.
  3. Forgetting to multiply a whole-number term when clearing fractions.
  4. Filled circle for << or >>; open circle for ≤\le or ≥\ge.
  5. Joining dots with a line for integers, or listing a real-number solution set.
  6. Leaving out the arrow when the solution set goes on for ever.