1. Conductors and capacitance
- In electrostatic equilibrium: E = 0 inside a conductor; excess charge resides on the outer surface; the conductor is an equipotential; just outside, E is normal to the surface. Free charges move through conductors; bound charges in insulators only shift within molecules.
- Capacitance ; unit farad (C V⁻¹); μF, nF, pF in practice. Depends on geometry and medium, not on Q.
- Isolated sphere: (R = 9 cm gives 10 pF; the Earth about 711 μF).
Formulas
- Capacitance
Key terms
- Capacitance
Ratio of the charge on a conductor to its potential (or on a capacitor’s plates to their potential difference).
- Farad
Capacitance that holds one coulomb per volt.
2. Parallel-plate capacitor
Plates of area A, separation d, charges ±Q: uniform field ; ; so (edge effects neglected).
Formulas
- Parallel-plate capacitor
3. Combinations
- Series: same Q on each; ; ; smaller than the smallest; the smallest C takes the largest V.
- Parallel: same V; ; ; larger than the largest.
- Mixed networks: reduce step by step; find Q on series branches and V across parallel ones.
Formulas
- Series and parallel
4. Energy stored
- (area under the V–Q line; formulae used, not derived, in the ISC scope).
- Energy density of the field: (J m⁻³).
- Connecting a charged (at ) to an uncharged : charge conserved, common ; energy is lost as heat.
- V = Q/C (C = 2.0 μF)
Formulas
- Energy stored
- Energy density
Key terms
- Energy density
Energy stored per unit volume of the electric field, ½ε₀E².
5. Dielectrics
- In a field a dielectric polarises (polar molecules align; non-polar molecules become induced dipoles); bound surface charges appear (− facing the + plate) and reduce the field inside to .
- Dielectric constant ; filled capacitor .
- Battery disconnected (Q fixed): C × K; V, E, U ÷ K. Battery connected (V fixed): C, Q, U × K; E unchanged.
Formulas
- Filled capacitor
Key terms
- Polarisation
Alignment or induction of molecular dipoles in a dielectric placed in a field.
- Dielectric constant
K = C with dielectric ÷ C in vacuum = ε/ε₀.
6. Capacitor partly filled with a slab
Slab of thickness t (t < d), constant K: , so . t = 0 gives ; t = d gives ; a metal slab (K → ∞) gives .
- slab with K = 4
Formulas
- Partial slab
Exam tips
- Derive C = ε₀A/d from E = σ/ε₀ and V = Ed.
- Series: common Q; parallel: common V.
- Battery on or off decides whether V or Q is fixed.
- Charge sharing: conserve Q; energy is lost.