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Moving Charges and Magnetic Field — Notes

6 sections 5 min readBeta

1. Oersted’s experiment and the definition of B

  • Oersted (1820): a compass needle near a current-carrying wire deflects, and the deflection reverses with the current: a current produces a magnetic field. Field lines of a straight wire are circles round it (right-hand grip rule).
  • A charge q moving with velocity v in a field B feels F⃗=q(v⃗×B⃗)\vec F = q(\vec v \times \vec B), of size qvBsin⁡θqvB\sin\theta, perpendicular to both v and B. This defines B: B=F/(qvsin⁡θ)B = F/(qv\sin\theta).
  • Unit: tesla, 1 T = 1 N A⁻¹ m⁻¹ = 1 N s C⁻¹ m⁻¹; 1 gauss = 10⁻⁴ T. No force on a charge at rest or moving along B.

Formulas

  • Magnetic force on a moving charge
    F⃗=q(v⃗×B⃗)\vec F = q\left(\vec v \times \vec B\right)

Key terms

Magnetic field (B)

Vector field defined by the force F = q(v × B) on a moving charge; unit tesla.

Tesla

Field in which a charge of 1 C moving at 1 m s⁻¹ perpendicular to the field feels 1 N.

2. The Biot–Savart law

dB⃗=μ04πI dl⃗×r⃗r3d\vec B = \dfrac{\mu_0}{4\pi}\dfrac{I\,d\vec l \times \vec r}{r^3}, size dB=μ04πI dlsin⁡θr2dB = \dfrac{\mu_0}{4\pi}\dfrac{I\,dl\sin\theta}{r^2}, with μ0=4π×10−7\mu_0 = 4\pi \times 10^{-7} T m A⁻¹.

  • dB⃗d\vec B is perpendicular to the plane of dl⃗d\vec l and r⃗\vec r; zero along the line of the element.
  • Compared with Coulomb’s law: both inverse-square and both obey superposition; but the source I dl⃗I\,d\vec l is a vector, the field depends on sin⁡θ\sin\theta and is perpendicular to r⃗\vec r (the electric field is along r⃗\vec r).

Formulas

  • Biot–Savart law
    dB⃗=μ04π I dl⃗×r⃗r3d\vec B = \dfrac{\mu_0}{4\pi}\,\dfrac{I\,d\vec l \times \vec r}{r^3}

Key terms

Permeability of free space

μ₀ = 4π × 10⁻⁷ T m A⁻¹; μ₀/4π = 10⁻⁷.

3. Circular coil: centre and axis

  • Centre of a coil of N turns, radius R: every element is at 90° to the line to the centre and at distance R, so B=μ0NI2RB = \dfrac{\mu_0NI}{2R} along the axis (right-hand grip rule).
  • Axis, distance x from the centre: components across the axis cancel in pairs; B=μ0NIR22(R2+x2)3/2B = \dfrac{\mu_0NIR^2}{2(R^2 + x^2)^{3/2}}. Far away, B≈μ0NIR2/2x3B \approx \mu_0NIR^2/2x^3.
  • Example: 40 turns, R = 8.0 cm, 0.60 A gives 1.88 × 10⁻⁴ T at the centre and 0.512 of that at x = 6.0 cm.
Directions computed from the Biot–Savart law: the parts across the axis cancel.
  • B(x)/B(0) = (1 + x²/R²)(−3/2)
At x = 0.75R the field is 0.8³ = 0.512 of the centre value (worked example 2).

Formulas

  • Centre of a coil
    B=μ0NI2RB = \dfrac{\mu_0NI}{2R}
  • Axis of a coil
    B=μ0NIR22(R2+x2)3/2B = \dfrac{\mu_0NIR^2}{2\left(R^2 + x^2\right)^{3/2}}

Key terms

Right-hand grip rule (coil)

Curl the fingers of the right hand along the current; the thumb gives the field at the centre.

4. Ampere’s circuital law and its uses

  • ∮B⃗⋅dl⃗=μ0Ienclosed\oint \vec B \cdot d\vec l = \mu_0 I_{\text{enclosed}} round any closed loop; currents outside do not count, opposite currents count with opposite signs. Useful when symmetry makes B constant along the loop.
  • Long straight wire: B=μ0I/2πrB = \mu_0I/2\pi r, circles round the wire.
  • Long solenoid: B=μ0nIB = \mu_0nI inside (n = turns per metre), uniform and along the axis; weak outside; independent of the radius.
  • Finite straight wire (formula only): B=μ0I4πa(sin⁡α+sin⁡β)B = \dfrac{\mu_0I}{4\pi a}(\sin\alpha + \sin\beta), angles from the perpendicular; long wire α=β=90∘\alpha = \beta = 90^\circ.
Drawn to scale: 8.0 cm wire, P 3.0 cm from its midpoint.
  • P on the perpendicular bisector: sin α
Once the wire is a few times longer than the distance a, the long-wire formula is a good approximation.

Formulas

  • Ampere’s circuital law
    ∮B⃗⋅dl⃗=μ0Ienc\oint \vec B \cdot d\vec l = \mu_0 I_{\text{enc}}
  • Long wire; long solenoid
    B=μ0I2πr,B=μ0nIB = \dfrac{\mu_0I}{2\pi r},\qquad B = \mu_0nI
  • Finite wire
    B=μ0I4πa(sin⁡α+sin⁡β)B = \dfrac{\mu_0I}{4\pi a}\left(\sin\alpha + \sin\beta\right)

Key terms

Amperian loop

Closed path chosen so that B is constant in size and along (or across) the path, making the line integral easy.

Solenoid

Long, closely wound coil; field inside μ₀nI.

5. Lorentz force and the motion of charges

  • F⃗=q(E⃗+v⃗×B⃗)\vec F = q(\vec E + \vec v \times \vec B). The magnetic part is perpendicular to v, so it does no work: speed and kinetic energy stay constant.
  • v⃗⊥B⃗\vec v \perp \vec B: circle, r=mv/qBr = mv/qB, T=2πm/qBT = 2\pi m/qB (independent of v), f=qB/2πmf = qB/2\pi m.
  • At angle θ: helix, r=mvsin⁡θ/qBr = mv\sin\theta/qB, pitch p=2πmvcos⁡θ/qBp = 2\pi mv\cos\theta/qB. Along B: straight line.
  • Crossed E and B: undeflected when v=E/Bv = E/B (velocity selector).

Formulas

  • Lorentz force
    F⃗=q(E⃗+v⃗×B⃗)\vec F = q\left(\vec E + \vec v \times \vec B\right)
  • Circular motion
    r=mvqB,T=2πmqBr = \dfrac{mv}{qB},\qquad T = \dfrac{2\pi m}{qB}

Key terms

Lorentz force

Total force q(E + v × B) on a charge moving in electric and magnetic fields.

Pitch

Distance a charge on a helix moves along the field in one revolution.

6. Forces on currents; the ampere and the coulomb

  • Conductor of length l: F⃗=I(l⃗×B⃗)\vec F = I(\vec l \times \vec B), F=BIlsin⁡θF = BIl\sin\theta (from nAlnAl electrons each feeling evdBsin⁡θev_dB\sin\theta, with I=nAevdI = nAev_d). Zero when the wire is along B.
  • Parallel wires: f=μ0I1I22πrf = \dfrac{\mu_0I_1I_2}{2\pi r} per unit length; like currents attract, unlike repel; equal and opposite forces.
  • Ampere: the steady current in each of two long, thin, parallel wires 1 m apart in vacuum that gives a force of 2 × 10⁻⁷ N per metre. Coulomb: the charge carried in 1 s by 1 A (1 C = 1 A s).

Formulas

  • Force on a conductor
    F⃗=I(l⃗×B⃗)\vec F = I\left(\vec l \times \vec B\right)
  • Parallel currents
    Fl=μ0I1I22πr\dfrac{F}{l} = \dfrac{\mu_0I_1I_2}{2\pi r}

Key terms

Ampere

Current in each of two long parallel wires 1 m apart in vacuum giving 2 × 10⁻⁷ N per metre between them.

Coulomb

Charge passing a point in 1 s when the current is 1 A.

Exam tips

  • Write the Biot–Savart law and the Lorentz force in vector form.
  • Convert cm to m; μ₀/4π = 10⁻⁷, μ₀/2π = 2 × 10⁻⁷.
  • Coils: N turns; solenoids: n turns per metre.
  • Directions: set up x, y, z axes and use the cross product; reverse for electrons.