1. Intermolecular forces and the gaseous state
This chapter is for formative assessment only (not in the annual theory paper). A gas is described by , , and . The state of a substance depends on the balance between thermal energy (which keeps molecules apart) and intermolecular forces (which pull them together): in a gas thermal energy dominates. Forces in brief: dispersion (all molecules, weak, grows with size), dipole–dipole (polar molecules), hydrogen bonding (H on N, O, F), ion–dipole. Units: 1 atm = 101.325 kPa = 760 mmHg = 1.01325 bar; .
| Force | Between | Strength |
|---|---|---|
| Dispersion | All molecules | Weak, grows with size |
| Dipole–dipole | Polar molecules | Moderate |
| Hydrogen bond | H on N/O/F and a lone pair | Strongest of the three |
| Ion–dipole | Ion and polar molecule | Strong |
Key terms
- Intermolecular force
An attraction between neighbouring molecules, much weaker than a chemical bond.
- Dispersion force
Attraction between temporary dipoles; present in all molecules.
- Liquefaction
Conversion of a gas into a liquid by cooling or compression.
2. Boyle’s and Charles’s laws
Boyle: at constant and , , so . against is a hyperbola; against is a straight line of slope .
Charles: at constant and , (in kelvin), so . against in °C is a straight line meeting at −273.15 °C.
Combined: .
Formulas
- Boyle
- Charles
- Combined gas law
Key terms
- Isotherm
A curve showing p against V at one temperature.
- Absolute zero
0 K = −273.15 °C, where the extrapolated volume of an ideal gas would be zero.
3. Gay-Lussac’s law, Avogadro’s law and the ideal gas equation
Gay-Lussac (pressure law): at constant and , . Avogadro: at the same and , ; equal volumes of gases have equal numbers of molecules. Together: .
R depends on units: 0.08314 L bar K⁻¹ mol⁻¹; 0.0821 L atm K⁻¹ mol⁻¹; 8.314 J K⁻¹ mol⁻¹; 62.36 L mmHg K⁻¹ mol⁻¹. (1 L bar = 100 J.)
| Units | R |
|---|---|
| L bar K⁻¹ mol⁻¹ | 0.08314 |
| L atm K⁻¹ mol⁻¹ | 0.0821 |
| J K⁻¹ mol⁻¹ | 8.314 |
| L mmHg K⁻¹ mol⁻¹ | 62.36 |
Formulas
- Ideal gas equation
Key terms
- Ideal gas
A hypothetical gas that obeys pV = nRT at all pressures and temperatures.
- Gas constant R
The constant in pV = nRT, equal to pV/nT; its value depends on the units.
4. Density, molar mass and Dalton’s law
Density and molar mass: and ; at fixed and density is proportional to molar mass.
Dalton’s law: , with and .
Gas collected over water: . Vapour pressure of water (mmHg): 17.5 at 20 °C, 23.8 at 25 °C, 26.7 at 27 °C, 31.8 at 30 °C, 55.3 at 40 °C.
| T / °C | 20 | 25 | 27 | 30 | 40 |
|---|---|---|---|---|---|
| Vapour pressure of water / mmHg | 17.5 | 23.8 | 26.7 | 31.8 | 55.3 |
Formulas
- Density of a gas
- Partial pressure
Key terms
- Partial pressure
The pressure a gas in a mixture would exert if it alone filled the container at the same temperature.
- Mole fraction
Moles of a component divided by total moles.
- Aqueous tension
The vapour pressure of water at the temperature of the experiment.
5. Deviations from ideality and the compressibility factor
Real gases deviate because (i) molecules have a finite volume (important at high ) and (ii) there are attractions (important at low and moderate ). A real gas is closest to ideal at low pressure and high temperature.
. ideal; attractions dominate; molecular volume dominates. Z against p: H₂ and He at 273 K start at 1 and rise; N₂ dips slightly then rises; CO₂ dips far below 1 then rises.
Formulas
- Compressibility factor
Key terms
- Compressibility factor
Z = pV/nRT, a measure of departure from ideal behaviour.
- Real gas
A gas that obeys pV = nRT only approximately, best at low pressure and high temperature.
6. van der Waals equation and liquefaction
. a (L² bar mol⁻²) corrects for attractions (larger a: easier to liquefy); b (L mol⁻¹) is the excluded volume per mole, about four times the actual volume of the molecules. Examples: He a = 0.0346, b = 0.0238; CO₂ a = 3.640, b = 0.0427.
Liquefaction: above the critical temperature Tc no pressure liquefies a gas; the critical pressure pc is the pressure needed at Tc. Tc: CO₂ 304.1 K, NH₃ 405.5 K, Cl₂ 417 K, O₂ 154.6 K, N₂ 126.2 K, H₂ 33.2 K. Gases with large a have high Tc.
| Gas | Tc / K | pc / bar |
|---|---|---|
| CO₂ | 304.1 | 73.8 |
| NH₃ | 405.5 | 113.5 |
| O₂ | 154.6 | 50.4 |
| N₂ | 126.2 | 33.9 |
| H₂ | 33.2 | 13.0 |
Formulas
- van der Waals equation
Key terms
- Excluded volume
The volume around each molecule into which the centres of other molecules cannot enter; b per mole.
- Critical temperature
The highest temperature at which a gas can be liquefied by pressure.
- Critical pressure
The pressure needed to liquefy a gas at its critical temperature.
Exam tips
Common mistakes
- Using temperature in °C, or mixing units of R with the units of p and V.
- Forgetting to subtract the vapour pressure of water for a gas collected over water.
- Saying Z < 1 means repulsion dominates (it is attraction).
- Calling b the actual volume of molecules (it is about four times that volume).
- Thinking a gas can always be liquefied by pressure alone (not above Tc).
How marks are usually awarded
- Numericals (2–3 marks): formula (1), substitution with correct units (1), answer with unit (1).
- Deviation questions: two assumptions that fail (1) + conditions for ideal behaviour (1).
- van der Waals: equation (1) + meaning of a and b (1).